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9y^2-36y-36=0
a = 9; b = -36; c = -36;
Δ = b2-4ac
Δ = -362-4·9·(-36)
Δ = 2592
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2592}=\sqrt{1296*2}=\sqrt{1296}*\sqrt{2}=36\sqrt{2}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-36\sqrt{2}}{2*9}=\frac{36-36\sqrt{2}}{18} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+36\sqrt{2}}{2*9}=\frac{36+36\sqrt{2}}{18} $
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